Currents and voltages in an heterogeneous earthΒΆ

Usually the subsurface is not uniform (otherwise Geophysics and Earth Sciences would be meaningless). Some analytics solutions exist for very simple cases such as a sphere in a uniform field or a layered Earth. In all others cases, the use of numerical modeling techniques is required to compute the response of a particular physical property distribution. We use the differential equations described in Equations for modeling DC phenomenona to achieve it. You can also see the article Leading Edge for more information about numerical techniques.

The animation below, taken from the Mont Isa case history shows an example of such computation to visualize the current distribution for different sources in a highly structure underground:



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Galvanic currents will flow towards regions of high conductivity and away from regions of high resistivity.

The Elura orebody (in New South Wales, Australia) show below is an example of a target with a range of electrical resistivities. Details are from I.G. Hone, Geoelectric Properties of the Elura Prospect, Cobar, NSW, in β€œThe Geophysics of the Elura Orebody, Cobar NSW,” 1980, Australian Society of Exploration Geophysicists.

DC methods
Figure 2. Click buttons for images a. through e.
a. The Elura ore body. Depth to top of gossan (in blue) is approximately 100 m.
b. A DC resistivity survey involves injecting current at one location and measuring resulting potentials at another location.
c. Current will flow. Current density increases within conductive regions, and decreases within resistive regions. 
d. Charges build up at interfaces between regions of different electrical conductivity.
e. Variations in charge distribution are detected as variations in distribution of potential, or voltage, at the surface. 
 
  Elura Orebody

Elura Orebody Electrical resistivities
Rock Type
Ohm-m
Overburden
12
Host rocks
200
Gossan
420
Mineralization (pyritic)
0.6
Mineralization (pyrrhotite)
0.6

Charge distributionΒΆ

../../_images/sig1_sig0.gif

One of the fundamental principles regarding current flow is that away from the current electrode, all the current that goes into a body must come out. There are no sources or sinks of current anywhere, except at the current electrode itself.

Because there are no sources or sinks of current in the earth (conservation of charge), the normal component of current density is constant across any boundary where conductivity changes. That is, all of the current that flows into one side of the boundary must flow out the other side. Also, since lines of equal potential in an electric field are perpendicular to current flow, the electric field perpendicular to the normal component of current at the boundaries must also be constant across the boundary. Therefore there are two boundary conditions that must hold across interfaces where conductivity changes:

  • the normal component of current density, \(J\), must be continuous, and

  • tangential components of electric field, \(E\), must be continuous.

Recall that Ohm’s law is \(J = \sigma E\). Since the normal component of \(J\) is continuous across a boundary where conductivity changes, the normal component of the \(E\)-field must NOT be equal. If \(\sigma_2 > \sigma_1\) then \(E_2 < E_1\). The following figure should clarify:

../../_images/sigma_E_relation.gif

The only way an electric field can change at a boundary is if there is a charge on the boundary. If the current is flowing from a resistive medium to a conductive medium, then the charge buildup will be negative. If the current flows from a conductive medium to a resistive medium, then the charge will be positive. This is illustrated in the diagram below-left, where the anomalous body (blue) is more conductive than the host (yellow). In the figure below- right, the change in \(E\)-field is illustrated for a field crossing from a resistive medium (yellow) into a more conductive zone (blue). Tangential components are unchanged, but normal components of \(E\) are different so that normal components of \(J\) can remain unchanged. This change in direction is the origin of the concept that current lines β€œconverge” upon entering a conductor, and β€œdiverge” upon entering a resistor (illustrated with cartoons of the ore body in Surveys).

../../_images/conductive_body.gif
../../_images/E_field.gif

In fact, the charge density that accumulates will be related to the ratio of the two conductivities:

../../_images/conductivity_ratio.gif
../../_images/Q_r_vector.gif

How are charges on boundaries related to DC resistivity surveying? Any electric charge produces an electric potential. The Coulomb electrostatic potential is given by

\[V(r) = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r}\]

All charge on the edges of a body produce their own electric potentials, and at the surface (or anywhere else), the total potential is the sum of the potentials due to the individual charges (principal of superposition). These potentials are what we measure as voltages, and they are caused by charges building up on boundaries where conductivity changes, which in turn are caused by the current being forced to flow by the transmitter. Of course we don’t measure absolute potential; rather, we measure the potential difference between two locations (say \(r_1\) and \(r_2\)).

../../_images/potential_difference.gif

You can visualize it with this two spheres example. Can you tell which one is conductive and which one is resistive?



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